Problem packetResearch packetR111
The exact maximum is C(11) = 44
Link to a section
The recorded result has been reproduced within its stated scope.
Recorded status: established
Recorded scope: binary cross-bifix-free codes whose words all have length 11
Complete recorded scope and conditions
{
"kind": "bounded",
"statement": "binary cross-bifix-free codes whose words all have length 11",
"bounds": {
"alphabet_size": {
"min": 2,
"max": 2
},
"word_length": {
"min": 11,
"max": 11
}
},
"exhaustive": true
}Originating problem: Maximum cross-bifix-free binary code of length 11
Authored record and scope
- Authored title
- The exact maximum is C(11) = 44
- Record type
- claim
- Stored status
- established
- Evidence grade
- reproduced
- Recorded scope data
- { "kind": "bounded", "statement": "binary cross-bifix-free codes whose words all have length 11", "bounds": { "alphabet_size": { "min": 2, "max": 2 }, "word_length": { "min": 11, "max": 11 } }, "exhaustive": true }
2Authored explanation
The answer is \[ C(11)=44. \] Chee, Kiah, Purkayastha, and Wang list 44 at \(n=11\), attained by their construction with parameter \(k=3\). Their Section III-A explains the upper certificate: the vertices are all bifix-free binary words of length \(n\), two vertices are adjacent when the words are mutually cross-bifix-free, and MaxCliqueDyn computes the largest clique. Table I marks 44 as optimal. Stanovnik, Moškon, and Mraz later reproduce \(S(2,11)=44\) in Table 1 and state that their values through length 16 agree with Chee et al.
A compact construction is \[ A=\{0001u1:u\in\{0,1\}^{6}\text{ and }u\text{ contains no }000\}. \] The number of six-bit words avoiding \(000\) is the tribonacci value 44. The executable certificate generates all of them and checks each of the \(44^2\cdot10=19{,}360\) ordered prefix-suffix comparisons.
The same certificate independently replays the later integer upper bound. Proposition 10 writes the maximum as \[ S(2,11)=\max\sum_{i=1}^{10}x_i y_{11-i}, \] where \(x_1=y_1=1\) and \[ x_i+y_i=\sum_{j=1}^{i-1}x_jy_{i-j}. \] Theorem 15 permits an optimum with \(x_i y_i=0\) for \(i>11/2\). Exhausting every choice through \(i=5\), followed by the two zero-side choices at each later level, produces 640 terminal states. Their largest objective is 44. This gives a short replay of the exact upper bound.
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3Evidence
A verification source is cited. This record has no executable replay attached.
Verification source: arxiv.org ↗, Yeow Meng Chee, Han Mao Kiah, Punarbasu Purkayastha, and Chengmin Wang, Cross-Bifix-Free Codes Within a Constant Factor of Optimality, IEEE Transactions on Information Theory 59 (2013), 4668-4674, Section III-A, Table I and the maximum-clique paragraph on page 4671; independently replayed in cbf11-artifact-code-and-sqn-certificate
4What was measured
5How it connects
Verifies (incoming)
- artifact
Recorded for
- problem
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Machine-readable record
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"slug": "cbf11-claim-exact-maximum-44",
"type": "claim",
"title": "The exact maximum is C(11) = 44",
"summary": "A 44-word construction and two published exact searches establish the value 44.",
"relevance": "This records a result, observation, or conjecture used to assess the target problem.",
"relevance_source": "derived",
"body": "The answer is\n\\[\nC(11)=44.\n\\]\nChee, Kiah, Purkayastha, and Wang list 44 at \\(n=11\\), attained by their construction with parameter \\(k=3\\). Their Section III-A explains the upper certificate: the vertices are all bifix-free binary words of length \\(n\\), two vertices are adjacent when the words are mutually cross-bifix-free, and MaxCliqueDyn computes the largest clique. Table I marks 44 as optimal. Stanovnik, Moškon, and Mraz later reproduce \\(S(2,11)=44\\) in Table 1 and state that their values through length 16 agree with Chee et al.\n\nA compact construction is\n\\[\nA=\\{0001u1:u\\in\\{0,1\\}^{6}\\text{ and }u\\text{ contains no }000\\}.\n\\]\nThe number of six-bit words avoiding \\(000\\) is the tribonacci value 44. The executable certificate generates all of them and checks each of the \\(44^2\\cdot10=19{,}360\\) ordered prefix-suffix comparisons.\n\nThe same certificate independently replays the later integer upper bound. Proposition 10 writes the maximum as\n\\[\nS(2,11)=\\max\\sum_{i=1}^{10}x_i y_{11-i},\n\\]\nwhere \\(x_1=y_1=1\\) and\n\\[\nx_i+y_i=\\sum_{j=1}^{i-1}x_jy_{i-j}.\n\\]\nTheorem 15 permits an optimum with \\(x_i y_i=0\\) for \\(i>11/2\\). Exhausting every choice through \\(i=5\\), followed by the two zero-side choices at each later level, produces 640 terminal states. Their largest objective is 44. This gives a short replay of the exact upper bound.",
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"relations": [
{
"slug": "R110",
"title": "Exact construction check and 640-state upper certificate",
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{
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}7Provenance
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