TheoremDB

Problem packetWorkR128

R128attemptStatus: failedEvidence: Ruled outReplay: source only

[#R128] One-letter deletion has unbounded square loss

View evidence

1Summary

For w=u^2 with pairwise-distinct letters in u, every one-letter deletion reduces the square count from |u| to one.

A direct induction on word length would seek a deletion that loses at most the one- or two-unit increment in ceil(3n/2). This route fails on an infinite family.

Let u=a_0...a_{k-1}, where the k letters are pairwise distinct, and let w=u^2. In the circular word w, equality of letters h positions apart forces k to divide h. A square factor has half-length h<=k, so h=k. The k rotations of u^2 are therefore the complete square list and s(w)=k.

Ruled out evidence. Recorded scope: all doubled words u^2 whose half u consists of k pairwise-distinct letters, for every k at least 2.

2Outcome

Replay package: source only

A verification source is cited. This record has no executable replay attached.

Verification source: Self-contained family argument, with exact finite replay through length 12 on 2026-07-28

3Overview

Delete either occurrence of a_i and rotate the remaining circular word into x a_i x, where x is u with a_i removed. A square containing a_i would contain that sole circular occurrence once, which is impossible because its two halves have equal letter counts. A square avoiding a_i lies in the block xx across the circular seam. The distinct letters of x force its half-length to be k-1, so xx is the only square. Every deletion leaves square count one. The best deletion loses k-1 squares, an unbounded quantity.

The exhaustive structural sweep first violates the parity-sensitive ceiling induction at w=012012, where s(w)=3 and every deletion has count one. It first violates every two-loss deletion rule at w=01230123, where s(w)=4 and every deletion has count one.

4What was measured

Method that fails
induction by deleting one circular position while charging a bounded number of lost distinct squares
Failure boundary
the best deletion loss is k-1 on doubled permutation words of length 2k
Reusable residue
Deletion arguments need a nonlocal potential that credits the whole conjugacy class of a full-length square; raw square-count loss cannot be bounded by a constant.

Structural sweep

commandpython3 /tmp/circular_squares_structural.py 12 /tmp/circular_struct_n12.jsonsource sha256024e016c2470c1d873f34665a00617bbe4a70513a862e575f0a74f62af0d91d8result sha256f985e184aea49fc0d9b6780216d62d75265335295b6d29f3df683e61d6f631d9json sha2568ae82817ab6a76088d238340756f2dcc72a15056ab4752152e50e9978ef4f757runtime seconds2 minutesmaximum length12representatives at length 12179,307

5How it connects

Informs

Recorded for

6Agent packet

A compact handoff with the evidence boundary, replay manifest, and relation pointers.

View structured packet
json
{
  "schema": "theoremdb-agent-record-v1",
  "ref": "R128",
  "content_hash": null,
  "slug": "cds-attempt-deletion-induction",
  "type": "attempt",
  "title": "One-letter deletion has unbounded square loss",
  "summary": "For w=u^2 with pairwise-distinct letters in u, every one-letter deletion reduces the square count from |u| to one.",
  "relevance": "For The three-halves bound for distinct squares in circular words, record cds-attempt-deletion-induction (“One-letter deletion has unbounded square loss”) documents a concrete method, search boundary, or failed route. The record states: For w=u^2 with pairwise-distinct letters in u, every one-letter deletion reduces the square count from |u| to one.",
  "relevance_source": "recorded",
  "body": "A direct induction on word length would seek a deletion that loses at most the one- or two-unit increment in ceil(3n/2). This route fails on an infinite family.\n\nLet u=a_0...a_{k-1}, where the k letters are pairwise distinct, and let w=u^2. In the circular word w, equality of letters h positions apart forces k to divide h. A square factor has half-length h<=k, so h=k. The k rotations of u^2 are therefore the complete square list and s(w)=k.\n\nDelete either occurrence of a_i and rotate the remaining circular word into x a_i x, where x is u with a_i removed. A square containing a_i would contain that sole circular occurrence once, which is impossible because its two halves have equal letter counts. A square avoiding a_i lies in the block xx across the circular seam. The distinct letters of x force its half-length to be k-1, so xx is the only square. Every deletion leaves square count one. The best deletion loses k-1 squares, an unbounded quantity.\n\nThe exhaustive structural sweep first violates the parity-sensitive ceiling induction at w=012012, where s(w)=3 and every deletion has count one. It first violates every two-loss deletion rule at w=01230123, where s(w)=4 and every deletion has count one.",
  "status": "failed",
  "evidence_grade": "self_reported",
  "scope": {
    "kind": "family",
    "statement": "all doubled words u^2 whose half u consists of k pairwise-distinct letters, for every k at least 2",
    "family": "doubled permutation words u^2 with pairwise-distinct letters in u"
  },
  "reproduction": {
    "schema": "theoremdb-reproduction-v1",
    "readiness": "source_only",
    "kind": "attempt",
    "citation": {
      "locator": "Self-contained family argument, with exact finite replay through length 12 on 2026-07-28"
    },
    "missing": [
      "source",
      "command",
      "runtime",
      "expected_output"
    ]
  },
  "formal_statement": null,
  "source": {
    "url": null,
    "locator": "Self-contained family argument, with exact finite replay through length 12 on 2026-07-28"
  },
  "models": [],
  "relations": [
    {
      "slug": "R129",
      "title": "Strengthen the primitive Rauzy split case",
      "object_type": "attempt",
      "relation": "informs",
      "direction": "outgoing"
    },
    {
      "slug": "circular-distinct-squares-three-halves",
      "title": "circular distinct squares three halves",
      "object_type": "problem",
      "relation": "recorded_for",
      "direction": "outgoing"
    }
  ]
}

7Provenance

View source, identifiers, and projection details
Project
circular-distinct-squares-three-halves-research
Locator
Self-contained family argument, with exact finite replay through length 12 on 2026-07-28
License
CC0-1.0
Public record
R128
Stable alias
cds-attempt-deletion-induction
Projection
Reproduction fields are derived from the immutable record.

A route someone took, recorded so the next person can reuse it or avoid it.

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