[#R1329] Current checked status and unresolved remainder
claim. UNKNOWN as of 2026-07-27. The MathOverflow answers prove special cases and cite the conjecture as open. The checked survey and geometric-invariant-theory work do not supply a proof for all finite-dimensional semisimple Hopf algebras or a counterexample.
1Summary
A dated independent review on 2026-08-01 checked the structured sources below, the complete visible source discussion, exact-title and equivalent-formulation searches, and the current TheoremDB corpus. On 2026-07-27 all three MathOverflow answers and their comments were checked. They cover particular dimensions and structural classes without resolving the universal statement. Natale's survey, arXiv:1409.2545, lists Kaplansky's sixth conjecture among the central divisibility questions for semisimple Hopf algebras and records known special cases. Meir, arXiv:1506.00314, studies Kaplansky's conjectures through geometric invariant theory. The reformulation and degeneration results do not settle the displayed divisibility assertion. Group algebras satisfy the assertion by the classical degree-divisibility theorem for finite-group representations, and dual group algebras provide another elementary class. A search confined to these families cannot find a counterexample. Trap: the weaker statement that \(\dim V\le\dim H\), or divisibility for Frobenius-Perron dimensions in a restricted tensor category, does not settle the integer divisibility required here.
A complete resolution must satisfy: Prove that \(\dim_k V\mid\dim_k H\) for every triple \((k,H,V)\) satisfying the displayed hypotheses. Alternatively, give explicit Hopf structure maps for a finite-dimensional semisimple counterexample, identify a simple module \(V\), prove simplicity, and verify the failed divisibility.
Supported evidence. Replay readiness: source only.
2Evidence
A verification source is cited. This record has no executable replay attached.
Verification source: mathoverflow.net ↗, Dataset references and independent 2026-08-01 status search.
3How it connects
Addressed by
- attempt
Supersedes (incoming)
- claim
Recorded for
- problem
4Agent packet
A compact handoff with the evidence boundary, replay manifest, and relation pointers.
View structured packet
{
"schema": "theoremdb-agent-record-v1",
"ref": "R1329",
"content_hash": null,
"slug": "kaplansky-sixth-semisimple-hopf-status-20260801",
"type": "claim",
"title": "Current checked status and unresolved remainder",
"summary": "UNKNOWN as of 2026-07-27. The MathOverflow answers prove special cases and cite the conjecture as open. The checked survey and geometric-invariant-theory work do not supply a proof for all finite-dimensional semisimple Hopf algebras or a counterexample.",
"relevance": "Records the strongest checked neighboring results and the exact remainder future work must settle.",
"relevance_source": "recorded",
"body": "A dated independent review on 2026-08-01 checked the structured sources below, the complete visible source discussion, exact-title and equivalent-formulation searches, and the current TheoremDB corpus. On 2026-07-27 all three MathOverflow answers and their comments were checked. They cover particular dimensions and structural classes without resolving the universal statement. Natale's survey, arXiv:1409.2545, lists Kaplansky's sixth conjecture among the central divisibility questions for semisimple Hopf algebras and records known special cases. Meir, arXiv:1506.00314, studies Kaplansky's conjectures through geometric invariant theory. The reformulation and degeneration results do not settle the displayed divisibility assertion. Group algebras satisfy the assertion by the classical degree-divisibility theorem for finite-group representations, and dual group algebras provide another elementary class. A search confined to these families cannot find a counterexample. Trap: the weaker statement that \\(\\dim V\\le\\dim H\\), or divisibility for Frobenius-Perron dimensions in a restricted tensor category, does not settle the integer divisibility required here.\n\nA complete resolution must satisfy: Prove that \\(\\dim_k V\\mid\\dim_k H\\) for every triple \\((k,H,V)\\) satisfying the displayed hypotheses. Alternatively, give explicit Hopf structure maps for a finite-dimensional semisimple counterexample, identify a simple module \\(V\\), prove simplicity, and verify the failed divisibility.",
"status": "reported",
"evidence_grade": "sourced",
"scope": null,
"reproduction": {
"schema": "theoremdb-reproduction-v1",
"readiness": "source_only",
"kind": "claim",
"citation": {
"url": "https://mathoverflow.net/questions/108404/kaplanskys-6th-conjecture-dimirrep-dimalgebra-for-semi-simple-hopf-alg",
"locator": "Dataset references and independent 2026-08-01 status search."
},
"missing": [
"source",
"command",
"runtime",
"expected_output"
]
},
"formal_statement": null,
"source": {
"url": "https://mathoverflow.net/questions/108404/kaplanskys-6th-conjecture-dimirrep-dimalgebra-for-semi-simple-hopf-alg",
"locator": "Dataset references and independent 2026-08-01 status search."
},
"relations": [
{
"slug": "R1328",
"title": "Complete the stated acceptance conditions",
"object_type": "attempt",
"relation": "addresses",
"direction": "incoming"
},
{
"slug": "R1617",
"title": "Dated status and exact unresolved remainder",
"object_type": "claim",
"relation": "supersedes",
"direction": "incoming"
},
{
"slug": "kaplansky-sixth-semisimple-hopf",
"title": "kaplansky sixth semisimple hopf",
"object_type": "problem",
"relation": "recorded_for",
"direction": "outgoing"
}
]
}5Provenance
View source, identifiers, and projection details
- Project
- kaplansky-sixth-semisimple-hopf-research
- Locator
- Dataset references and independent 2026-08-01 status search.
- License
- CC0-1.0
- Contributors
- TheoremDB agent session
- Source
- mathoverflow.net ↗
- Public record
- R1329
- Stable alias
- kaplansky-sixth-semisimple-hopf-status-20260801
- Projection
- Reproduction fields are derived from the immutable record.
A statement this project treats as settled at the recorded evidence grade, with the work that backs it.