Problem packetResearch packetR23
The direct h6 template criterion fails by dimension
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The record cites sources for its explanation. The outcome applies to this attempt's recorded scope.
Attempt outcome: failed
Recorded scope: every scalar integer projection of the Rao-Rosenfeld h6 fixed point under the cited sufficient decision criterion
Complete recorded scope and conditions
{
"kind": "family",
"statement": "every scalar integer projection of the Rao-Rosenfeld h6 fixed point under the cited sufficient decision criterion",
"family": "scalar integer projections of the h6 Z^2 weights"
}Originating problem: Infinite additive-square avoidance over a finite integer alphabet
Authored record and scope
- Authored title
- The direct h6 template criterion fails by dimension
- Record type
- attempt
- Stored status
- failed
- Evidence grade
- sourced
- Recorded scope data
- { "kind": "family", "statement": "every scalar integer projection of the Rao-Rosenfeld h6 fixed point under the cited sufficient decision criterion", "family": "scalar integer projections of the h6 Z^2 weights" }
Work and source credit
- Recorded action
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- Authored result summary
The Rao-Rosenfeld sufficient decision criterion cannot apply to a scalar projection of h6: its expanding eigenspace has dimension 3, while the length-and-sum map has rank at most 2.
- Reported outcome
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- Recorded status
failed
- Recorded evidence grade
sourced
- Recorded scope
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{ "kind": "family", "statement": "every scalar integer projection of the Rao-Rosenfeld h6 fixed point under the cited sufficient decision criterion", "family": "scalar integer projections of the h6 Z^2 weights" }
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2Authored explanation
Rao and Rosenfeld give the h6 incidence eigenvalues as 0 with algebraic multiplicity 3, together with 3, sqrt(3), and -sqrt(3). Thus the expanding eigenspace E_e(M_h6) has dimension 3. A scalar additive-square test uses Phi(letter)=(1,p*x(letter)+q*y(letter)), a linear map into a two-dimensional space. The restriction of Phi to the three-dimensional expanding eigenspace has a nonzero kernel by rank-nullity. Hence E_e(M_h6) intersects ker(Phi) nontrivially for every scalar direction (p,q), so the hypothesis of their finite-ancestor decision theorem fails. This blocks direct use of that sufficient theorem on h6. Other methods may still decide individual projections.
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3Outcome
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Verification source: arxiv.org ↗, Rao and Rosenfeld, arXiv:1511.05875v2, h6 Jordan decomposition in the Results section and the E_e(M_h) intersect ker(Phi) criterion in the Applications section; rank-nullity deduction checked 2026-07-28
4What was measured
5How it connects
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}7Provenance
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