Problem packetLean verificationR863
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Originating problem: Determinants of the Fibonacci-sum matrix
Authored record and environment
- Authored title
- Fibonacci odd square cover
- Authored summary
- Lean proves that every Eulerian selected support is covered with odd multiplicity by finitely many contained support squares.
- Stored status
- draft
- Evidence grade
- unverified_formalization
- Lean world
- lean-4.33.0-rc1/mathlib4@4608056c77c52468b80773e8dcd585ef821c7c5e+theoremdb@d575c4e2ff28345440c4f8a42bf0178bcb3f6f41b703a45d9d1cbb709036f0dc
2Authored explanation
The proof works with arbitrary even sub-supports. A maximal incident vertex exposes a Fibonacci support square containing at least three current edges. Toggling that square preserves every row and column parity and strictly reduces the edge count, so well-founded induction produces the odd square cover. The two-square incidence bound then turns the cover into a four-edge partition.
3Formal statement
theorem fibSubmatrixSupport_has_odd_square_cover (n k : ℕ) (f : Fin k → Fin n) (g : Fin k → Fin n) (hf : f.Injective) (hg : g.Injective) (hrows : HasEvenRowSums ((fibSumMatrix n).submatrix f g)) (hcols : HasEvenColumnSums ((fibSumMatrix n).submatrix f g)) : ∃ faces : Finset (SelectedSupportSquare n k f g), ∀ edge ∈ fibSubmatrixSupport n k f g, Odd (faces.filter fun S => edge ∈ S.edges).card := by
-- Kernel-checked square-toggle induction in OddSquareCover.leanContinue this work
Replay material: partial
4Verification
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Verification source: mathoverflow.net ↗, formal/lean/TheoremDB/Fibonacci/OddSquareCover.lean
5What was measured
6How it connects
Depended on by
- formalization
Depends on
- formalization
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Machine-readable record
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{
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"ref": "R863",
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"slug": "fib-formalization-support-card-divisibility",
"type": "formalization",
"title": "Fibonacci odd square cover",
"summary": "Lean proves that every Eulerian selected support is covered with odd multiplicity by finitely many contained support squares.",
"relevance": "This supplies the graph-theoretic core of Fibonacci support divisibility.",
"relevance_source": "recorded",
"body": "The proof works with arbitrary even sub-supports. A maximal incident vertex exposes a Fibonacci support square containing at least three current edges. Toggling that square preserves every row and column parity and strictly reduces the edge count, so well-founded induction produces the odd square cover. The two-square incidence bound then turns the cover into a four-edge partition.",
"status": "draft",
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"citation": {
"url": "https://mathoverflow.net/questions/513340/is-the-determinant-of-this-fibonacci-sum-indicator-matrix-always-1-0-or/513372",
"locator": "formal/lean/TheoremDB/Fibonacci/OddSquareCover.lean"
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"formal_statement": "theorem fibSubmatrixSupport_has_odd_square_cover (n k : ℕ) (f : Fin k → Fin n) (g : Fin k → Fin n) (hf : f.Injective) (hg : g.Injective) (hrows : HasEvenRowSums ((fibSumMatrix n).submatrix f g)) (hcols : HasEvenColumnSums ((fibSumMatrix n).submatrix f g)) : ∃ faces : Finset (SelectedSupportSquare n k f g), ∀ edge ∈ fibSubmatrixSupport n k f g, Odd (faces.filter fun S => edge ∈ S.edges).card := by\n -- Kernel-checked square-toggle induction in OddSquareCover.lean",
"source": {
"url": "https://mathoverflow.net/questions/513340/is-the-determinant-of-this-fibonacci-sum-indicator-matrix-always-1-0-or/513372",
"locator": "formal/lean/TheoremDB/Fibonacci/OddSquareCover.lean"
},
"models": [],
"relations": [
{
"slug": "R861",
"title": "Fibonacci support divisibility condition",
"object_type": "formalization",
"relation": "depends_on",
"direction": "incoming"
},
{
"slug": "R865",
"title": "Fibonacci support four-cycle classification",
"object_type": "formalization",
"relation": "depends_on",
"direction": "outgoing"
}
]
}8Provenance
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