TheoremDB

Problem packetWorkR342

R342attemptStatus: failed as complete proofEvidence: Incomplete methodReplay: source onlyexhaustive over its scope

[#R342] Prove the conjecture by induction through alpha-labelings

View evidenceOpen source ↗

1Summary

Alpha-labelings compose, so an induction that keeps one would close the conjecture. It cannot: alpha-labelings fail to exist from seven vertices up, and the count of exceptions keeps growing.

The route is attractive because alpha-labelings, unlike graceful labelings in general, survive the natural joins. If every tree had one, an induction on the tree order would go through, and much of the literature's composition machinery is built on exactly that property.

The route cannot be completed. The smallest counterexample is the spider with edges 0-1 1-2 0-3 3-4 0-5 5-6 on seven vertices, and the count of trees with no alpha-labeling grows from there: n=7: 1, n=8: 2, n=9: 5, n=10: 11, n=11: 22, n=12: 44, n=13: 82, n=14: 147, n=15: 254. An induction that carries an alpha-labeling as its hypothesis stops at a set of trees that keeps getting larger, so it cannot reach every tree at any size.

Incomplete method evidence. Recorded scope: tested against every tree on at most 15 vertices.

2Outcome

Replay package: source only

A verification source is cited. This record has no executable replay attached.

Verification source: arxiv.org ↗, research/graceful-trees/checks.py --max-n 15

3Overview

One qualifier, since it points at what the route is still good for. Those trees are a falling share of all trees, 10.6% at n=9 down to 3.3% at n=15, so the alpha route covers most trees at the sizes that can be counted, including every caterpillar. It is a partial method with a measured boundary, and whether that boundary thins out asymptotically is itself open.

4Where it stops

alpha-labelings do not exist for all trees

5What was measured

Smallest witness n
7
Smallest witness edges
0–1, 1–2, 0–3, 3–4, 0–5, 5–6
Alpha free count at max n
254
Alpha free share at max n
3.3%

Alpha free share peak

n9percent10.6%

6How it connects

Attempts

Recorded for

7Agent packet

A compact handoff with the evidence boundary, replay manifest, and relation pointers.

View structured packet
json
{
  "schema": "theoremdb-agent-record-v1",
  "ref": "R342",
  "content_hash": null,
  "slug": "gtc-attempt-alpha-induction",
  "type": "attempt",
  "title": "Prove the conjecture by induction through alpha-labelings",
  "summary": "Alpha-labelings compose, so an induction that keeps one would close the conjecture. It cannot: alpha-labelings fail to exist from seven vertices up, and the count of exceptions keeps growing.",
  "relevance": "For Graceful tree conjecture, record gtc-attempt-alpha-induction (“Prove the conjecture by induction through alpha-labelings”) documents a concrete method, search boundary, or failed route. The record states: Alpha-labelings compose, so an induction that keeps one would close the conjecture.",
  "relevance_source": "recorded",
  "body": "The route is attractive because alpha-labelings, unlike graceful labelings in general, survive the natural joins. If every tree had one, an induction on the tree order would go through, and much of the literature's composition machinery is built on exactly that property.\n\nThe route cannot be completed. The smallest counterexample is the spider with edges 0-1 1-2 0-3 3-4 0-5 5-6 on seven vertices, and the count of trees with no alpha-labeling grows from there: n=7: 1, n=8: 2, n=9: 5, n=10: 11, n=11: 22, n=12: 44, n=13: 82, n=14: 147, n=15: 254. An induction that carries an alpha-labeling as its hypothesis stops at a set of trees that keeps getting larger, so it cannot reach every tree at any size.\n\nOne qualifier, since it points at what the route is still good for. Those trees are a falling share of all trees, 10.6% at n=9 down to 3.3% at n=15, so the alpha route covers most trees at the sizes that can be counted, including every caterpillar. It is a partial method with a measured boundary, and whether that boundary thins out asymptotically is itself open.",
  "status": "failed_as_complete_proof",
  "evidence_grade": "reproduced",
  "scope": {
    "kind": "bounded",
    "statement": "tested against every tree on at most 15 vertices",
    "bounds": {
      "n": {
        "max": 15
      }
    },
    "exhaustive": true
  },
  "reproduction": {
    "schema": "theoremdb-reproduction-v1",
    "readiness": "source_only",
    "kind": "attempt",
    "citation": {
      "url": "https://arxiv.org/abs/1403.1564",
      "locator": "research/graceful-trees/checks.py --max-n 15"
    },
    "missing": [
      "source",
      "command",
      "runtime",
      "expected_output"
    ]
  },
  "formal_statement": null,
  "source": {
    "url": "https://arxiv.org/abs/1403.1564",
    "locator": "research/graceful-trees/checks.py --max-n 15"
  },
  "models": [],
  "relations": [
    {
      "slug": "R347",
      "title": "The smallest tree with no alpha-labeling has seven vertices",
      "object_type": "claim",
      "relation": "constrains",
      "direction": "incoming"
    },
    {
      "slug": "R346",
      "title": "Trees with no alpha-labeling: the count doubles, the share peaks and falls",
      "object_type": "claim",
      "relation": "constrains",
      "direction": "incoming"
    },
    {
      "slug": "graceful-tree-conjecture",
      "title": "Graceful tree conjecture",
      "object_type": "problem",
      "relation": "attempts",
      "direction": "outgoing"
    },
    {
      "slug": "graceful-tree-conjecture",
      "title": "graceful tree conjecture",
      "object_type": "problem",
      "relation": "recorded_for",
      "direction": "outgoing"
    }
  ]
}

8Provenance

View source, identifiers, and projection details
Project
graceful-tree-conjecture
Locator
research/graceful-trees/checks.py --max-n 15
License
CC-BY-4.0
Contributors
Philip Weiss, TheoremDB graceful-tree reproduction
Public record
R342
Stable alias
gtc-attempt-alpha-induction
Projection
Reproduction fields are derived from the immutable record.

A route someone took, recorded so the next person can reuse it or avoid it.

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