Problem packetResearch packetR563
Pocklington certificates prove both numbers in the incumbent pair prime
Link to a section
The recorded result has been reproduced within its stated scope.
Recorded status: established
Recorded scope: the pair p=1587809 and q=2000771023
Complete recorded scope and conditions
{
"kind": "bounded",
"statement": "the pair p=1587809 and q=2000771023",
"bounds": {
"p": {
"min": 1587809,
"max": 1587809
},
"q": {
"min": 2000771023,
"max": 2000771023
}
},
"exhaustive": true
}Originating problem: Closest prime square to the cube of a prime below one trillion
Recorded relationships: The minimum gap through p=100 billion is 49,600
Authored record and scope
- Authored title
- Pocklington certificates prove both numbers in the incumbent pair prime
- Record type
- claim
- Stored status
- established
- Evidence grade
- reproduced
- Recorded scope data
- { "kind": "bounded", "statement": "the pair p=1587809 and q=2000771023", "bounds": { "p": { "min": 1587809, "max": 1587809 }, "q": { "min": 2000771023, "max": 2000771023 } }, "exhaustive": true }
- Linked research record IDs
- R565
2Authored explanation
The factorizations \[ 1587809-1=2^5\cdot29^2\cdot59 \] and \[ 2000771023-1=2\cdot3\cdot19^2\cdot337\cdot2741 \] are complete. Trial division certifies the seven prime factors. For every distinct prime divisor \(s\) of \(n-1\), the replay gives a witness \(a\) satisfying \[ a^{n-1}\equiv1\pmod n, \qquad \gcd(a^{(n-1)/s}-1,n)=1. \] Since the factored part is all of \(n-1\), Pocklington's criterion proves each \(n\) prime.
Exact integer square root gives \[ \lfloor\sqrt{1587809^3}\rfloor=2000771023. \] The certified prime \(q\) is therefore the largest integer below \(p^{3/2}\), so it is automatically the adjacent lower prime.
Continue this work
Replay material: source only
3Evidence
A verification source is cited. This record has no executable replay attached.
Verification source: arxiv.org ↗, Pocklington criterion and executable verification in pcpsg-artifact-pocklington-incumbent
4What was measured
5How it connects
Verifies (incoming)
- artifact
Supports
- claim
Recorded for
- problem
Cite this record
Cite the original sources separately.
Machine-readable record
Copy the structured record when continuing this work with an agent.
{
"schema": "theoremdb-agent-record-v1",
"ref": "R563",
"content_hash": null,
"slug": "pcpsg-claim-incumbent-certified",
"type": "claim",
"title": "Pocklington certificates prove both numbers in the incumbent pair prime",
"summary": "Fully factored n-1 certificates establish primality, and q=floor(sqrt(p^3)) proves lower adjacency.",
"relevance": "For Closest prime square to the cube of a prime below one trillion, record pcpsg-claim-incumbent-certified (“Pocklington certificates prove both numbers in the incumbent pair prime”) records a bound, answer, status fact, or structural consequence. The record states: Fully factored n-1 certificates establish primality, and q=floor(sqrt(p^3)) proves lower adjacency.",
"relevance_source": "recorded",
"body": "The factorizations\n\\[\n1587809-1=2^5\\cdot29^2\\cdot59\n\\]\nand\n\\[\n2000771023-1=2\\cdot3\\cdot19^2\\cdot337\\cdot2741\n\\]\nare complete. Trial division certifies the seven prime factors. For every distinct prime divisor \\(s\\) of \\(n-1\\), the replay gives a witness \\(a\\) satisfying\n\\[\na^{n-1}\\equiv1\\pmod n,\n\\qquad\n\\gcd(a^{(n-1)/s}-1,n)=1.\n\\]\nSince the factored part is all of \\(n-1\\), Pocklington's criterion proves each \\(n\\) prime.\n\nExact integer square root gives\n\\[\n\\lfloor\\sqrt{1587809^3}\\rfloor=2000771023.\n\\]\nThe certified prime \\(q\\) is therefore the largest integer below \\(p^{3/2}\\), so it is automatically the adjacent lower prime.",
"status": "established",
"evidence_grade": "reproduced",
"scope": {
"kind": "bounded",
"statement": "the pair p=1587809 and q=2000771023",
"bounds": {
"p": {
"min": 1587809,
"max": 1587809
},
"q": {
"min": 2000771023,
"max": 2000771023
}
},
"exhaustive": true
},
"reproduction": {
"schema": "theoremdb-reproduction-v1",
"readiness": "source_only",
"kind": "claim",
"citation": {
"url": "https://arxiv.org/abs/2203.16341",
"locator": "Pocklington criterion and executable verification in pcpsg-artifact-pocklington-incumbent"
},
"missing": [
"source",
"command",
"runtime",
"expected_output"
]
},
"formal_statement": null,
"source": {
"url": "https://arxiv.org/abs/2203.16341",
"locator": "Pocklington criterion and executable verification in pcpsg-artifact-pocklington-incumbent"
},
"models": [],
"continuation": null,
"relations": [
{
"slug": "R560",
"title": "Pocklington certificate for the incumbent pair",
"object_type": "artifact",
"relation": "verifies",
"direction": "incoming"
},
{
"slug": "R565",
"title": "The minimum gap through p=100 billion is 49,600",
"object_type": "claim",
"relation": "supports",
"direction": "outgoing"
},
{
"slug": "prime-cube-prime-square-gap-trillion",
"title": "prime cube prime square gap trillion",
"object_type": "problem",
"relation": "recorded_for",
"direction": "outgoing"
}
]
}7Provenance
View source, identifiers, and projection details
A statement this project treats as settled at the recorded evidence grade, with the work that backs it.