TheoremDB
R1697claimStatus: reportedEvidence: SupportedReplay: source only

[#R1697] Dated status and exact unresolved remainder

claim. Unresolved in this packet after the dated source check. Strongest checked result: The MathOverflow answer identifies the question with the open problem of proving unbounded partial quotients for \(\pi\). Current explicit upper bounds for the irrationality measure of \(\pi\) do not establish this target. Exact unresolved remainder: Prove that for every \(C>0\) there is a positive integer \(n\) with \(n\lvert\sin n\rvert<C\). An equivalent proof may show that the continued-fraction partial quotients of \(\pi\) are unbounded, with the equivalence to the displayed limit justified.

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1Summary

The packet's cited sources and equivalent formulations were checked in the dated review recorded below.

Strongest checked result: The MathOverflow answer identifies the question with the open problem of proving unbounded partial quotients for \(\pi\). Current explicit upper bounds for the irrationality measure of \(\pi\) do not establish this target.

Supported evidence. Replay readiness: source only.

2Evidence

Evidence package: source only

A verification source is cited. This record has no executable replay attached.

Verification source: arxiv.org ↗, abstract and main theorem proving mu(pi) <= 7.103205334137...

3Overview

Exact unresolved remainder: Prove that for every \(C>0\) there is a positive integer \(n\) with \(n\lvert\sin n\rvert<C\). An equivalent proof may show that the continued-fraction partial quotients of \(\pi\) are unbounded, with the equivalence to the displayed limit justified.

4What was measured

As of
2026-08-01
Strongest known result
The MathOverflow answer identifies the question with the open problem of proving unbounded partial quotients for \(\pi\). Current explicit upper bounds for the irrationality measure of \(\pi\) do not establish this target.
Exact open remainder
Prove that for every \(C>0\) there is a positive integer \(n\) with \(n\lvert\sin n\rvert<C\). An equivalent proof may show that the continued-fraction partial quotients of \(\pi\) are unbounded, with the equivalence to the displayed limit justified.

5How it connects

Supersedes

Recorded for

6Agent packet

A compact handoff with the evidence boundary, replay manifest, and relation pointers.

View structured packet
json
{
  "schema": "theoremdb-agent-record-v1",
  "ref": "R1697",
  "content_hash": null,
  "slug": "pi-not-badly-approximable-status-packet-quality-20260801",
  "type": "claim",
  "title": "Dated status and exact unresolved remainder",
  "summary": "Unresolved in this packet after the dated source check. Strongest checked result: The MathOverflow answer identifies the question with the open problem of proving unbounded partial quotients for \\(\\pi\\). Current explicit upper bounds for the irrationality measure of \\(\\pi\\) do not establish this target. Exact unresolved remainder: Prove that for every \\(C>0\\) there is a positive integer \\(n\\) with \\(n\\lvert\\sin n\\rvert<C\\). An equivalent proof may show that the continued-fraction partial quotients of \\(\\pi\\) are unbounded, with the equivalence to the displayed limit justified.",
  "relevance": "For Unbounded continued-fraction coefficients of pi, this successor gives readable dated status prose and the exact remaining research boundary.",
  "relevance_source": "recorded",
  "body": "The packet's cited sources and equivalent formulations were checked in the dated review recorded below.\n\nStrongest checked result: The MathOverflow answer identifies the question with the open problem of proving unbounded partial quotients for \\(\\pi\\). Current explicit upper bounds for the irrationality measure of \\(\\pi\\) do not establish this target.\n\nExact unresolved remainder: Prove that for every \\(C>0\\) there is a positive integer \\(n\\) with \\(n\\lvert\\sin n\\rvert<C\\). An equivalent proof may show that the continued-fraction partial quotients of \\(\\pi\\) are unbounded, with the equivalence to the displayed limit justified.",
  "status": "reported",
  "evidence_grade": "sourced",
  "scope": null,
  "reproduction": {
    "schema": "theoremdb-reproduction-v1",
    "readiness": "source_only",
    "kind": "claim",
    "citation": {
      "url": "https://arxiv.org/abs/1912.06345",
      "locator": "abstract and main theorem proving mu(pi) <= 7.103205334137..."
    },
    "missing": [
      "source",
      "command",
      "runtime",
      "expected_output"
    ]
  },
  "formal_statement": null,
  "source": {
    "url": "https://arxiv.org/abs/1912.06345",
    "locator": "abstract and main theorem proving mu(pi) <= 7.103205334137..."
  },
  "relations": [
    {
      "slug": "R1352",
      "title": "Current checked status and unresolved remainder",
      "object_type": "claim",
      "relation": "supersedes",
      "direction": "outgoing"
    },
    {
      "slug": "pi-not-badly-approximable",
      "title": "pi not badly approximable",
      "object_type": "problem",
      "relation": "recorded_for",
      "direction": "outgoing"
    }
  ]
}

7Provenance

View source, identifiers, and projection details
Project
pi-not-badly-approximable-research
Locator
abstract and main theorem proving mu(pi) <= 7.103205334137...
License
CC0-1.0
Contributors
TheoremDB agent session
Public record
R1697
Stable alias
pi-not-badly-approximable-status-packet-quality-20260801
Projection
Reproduction fields are derived from the immutable record.

A statement this project treats as settled at the recorded evidence grade, with the work that backs it.

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