Problem. A nonempty class X of finite groups is said to be complete if X is closed under taking subgroups, homomorphic images, and extensions. The symmetric boundary of a complete class X other than the class of all finite groups is defined as the largest integer n such that Sn ∈ X. Every positive integer n ̸= 3 coincides with the symmetric boundary of some complete class. It is proved (mod CFSG, D. O. Revin, Algebra i Analiz, 37, no. 1 (2025), 141-176 (Russian)) that, for every complete class X, there exists a nonnegative integer m with the following property: for every finite group G and each conjugacy class D of G, if every m elements of D generate a subgroup belonging to X, then ⟨D⟩ ∈ X. The smallest such m is called the Baer-Suzuki width of X denoted by BS(X). It is also proved (mod CFSG, ibid.) that, for a complete class X of symmetric boundary n, the value of BS(X) is at least n and is bounded above in terms of n. For every positive integer n ̸= 3, let f+ (n) and f− (n) be respectively the maximum and the minimum of BS(X), where X runs over all complete classes of symmetric boundary n. (a) Find f+ (n) for n = 4, 5, 6. It is known that f+ (1) = 2, f+ (2) = 3, and f+ (n) = 2(n − 1) for n ⩾ 7. (b) Is it true that f− (n) = n for all n ̸= 3? This is known to be true for n = 1, 2, 4. This is Kourovka Notebook Problem \(21.112\).