[#P2706] Worst nearest-neighbor tour on a ten-vertex graph metric
Problem. For each connected simple graph \(H\) on labeled vertices \(\{0,\ldots,9\}\), use shortest-path distance as a complete metric. Starting at \(0\), repeatedly visit the nearest unvisited vertex, breaking ties by the smaller label, then return to \(0\). What is the largest ratio between this tour length and the optimal traveling-salesperson tour length?
1Context
Twenty thousand seeded connected graphs give a lower bound of 18/11.
2Remarks
Remark 1. The tie rule makes the nearest-neighbor tour deterministic.
Remark 2. The optimum ranges over all Hamiltonian cycles in the complete shortest-path metric.
3What counts as a solution
- Give a connected graph attaining the maximum ratio and a complete enumeration or metric certificate excluding every larger ratio.
1Status
Current status (The certified ratio lies between 18/11 and 11/5). An explicit graph gives 18/11, while a finite integer refinement of the classical nearest-neighbor analysis gives the universal upper bound 11/5.[1]
1Records
Notes and companion material
Original intake status. UNKNOWN as of 2026-07-25. An explicit graph gives 18/11, while a finite integer refinement of the classical nearest-neighbor analysis gives the universal upper bound 11/5. The checked sources do not settle the full acceptance condition.
- The dated packet audit checked the exact title, parameter, and the terminology used by the cited primary literature.
- The strongest recorded neighboring result is: An explicit graph gives 18/11, while a finite integer refinement of the classical nearest-neighbor analysis gives the universal upper bound 11/5.
- The controlled TheoremDB corpus was checked for equivalent formulations and contains no duplicate published target.
Recorded example 1. The incumbent graph has edges 02,03,17,18,19,23,25,26,27,45,48,56,78,89.
Computational notes
- Exact all-pairs shortest paths and Held-Karp optimization were run on 20000 seeded graphs. For the displayed graph, nearest neighbor follows 0,2,3,5,4,8,1,7,6,9 and has length 18, while the exact optimum is 11, giving ratio 18/11.
How the 4 records connect
ProblemWorst nearest-neighbor tour on a ten-vertex graph metric
- Computation 1The certified ratio lies between 18/11 and 11/5in this packetReproduced
- Artifact 1Exact verifier for the 18/11 graphverifiesReproduced
- Artifact 2Exhaustive integer certificate for the 11/5 upper boundverifiesReproduced
- Route 1A graph-level exclusion certificate remains openinformsSupported
2See also
- Largest subtour-LP gap among eight-vertex graph metricscombinatorial optimization
- Largest cyclic winning margin for six disjoint six-sided dicecombinatorial optimization
- Unique Games conjectureapproximation algorithms
How to cite
TheoremDB contributors, “Worst nearest-neighbor tour on a ten-vertex graph metric,” TheoremDB research memory, snapshot of July 25, 2026. https://theoremdb.org/statements/nearest-neighbor-graph-metric-tenThis page as plain text: nearest-neighbor-graph-metric-ten.md
This problem includes 4 records joined by 3 typed links, sourced from doi.org[1], current as of July 25, 2026.
1References
- Packet source. Daniel J. Rosenkrantz, Richard E. Stearns, and Philip M. Lewis, II, “An Analysis of Several Heuristics for the Traveling Salesman Problem”. SIAM Journal on Computing 6(3) (1977), 563-581. DOI 10.1137/0206041. Daniel J. Rosenkrantz, Richard E. Stearns, and Philip M. Lewis II, An Analysis of Several Heuristics for the Traveling Salesman Problem, SIAM Journal on Computing 6 (1977), 563-581, Theorem 1 and Lemma 1; exact finite certificates in this dataset; Rosenkrantz, Stearns, and Lewis, SIAM Journal on Computing 6 (1977), proof of Lemma 1, especially inequality (2.1), and proof of Theorem 1; finite integer enumeration in this artifact; Rosenkrantz, Stearns, and Lewis, An Analysis of Several Heuristics for the Traveling Salesman Problem, Sections 1 and 2; focused web and bibliographic search on 2026-07-25. ↗journal article · primary source · version of record · checked 2026-07-25Source use: original summary.The certified ratio lies between 18/11 and 11/5. An explicit graph gives 18/11, while a finite integer refinement of the classical nearest-neighbor analysis gives the universal upper bound 11/5. Exhaustive integer certificate for the 11/5 upper bound. A 106,678-sequence enumeration applies every Rosenkrantz edge inequality at each possible integral optimum. A graph-level exclusion certificate remains open. The classical source proves a general metric bound; this record sharpens it for ten unweighted graph metrics without enumerating all graph realizations.Also cited at Daniel J. Rosenkrantz, Richard E. Stearns, and Philip M. Lewis II, An Analysis of Several Heuristics for the Traveling Salesman Problem, SIAM Journal on Computing 6 (1977), 563-581, Theorem 1 and Lemma 1; exact finite certificates in this dataset.Also cited at Rosenkrantz, Stearns, and Lewis, An Analysis of Several Heuristics for the Traveling Salesman Problem, Sections 1 and 2; focused web and bibliographic search on 2026-07-25.Also cited at Rosenkrantz, Stearns, and Lewis, SIAM Journal on Computing 6 (1977), proof of Lemma 1, especially inequality (2.1), and proof of Theorem 1; finite integer enumeration in this artifact.For Worst nearest-neighbor tour on a ten-vertex graph metric: The classical source proves a general metric bound; this record sharpens it for ten unweighted graph metrics without enumerating all graph realizations.Source named by the research packet.
Original CC0 finite worst-case heuristic target.