Problem packetResearch packetR520
The Moore bound gives a universal ceiling of 24
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The recorded evidence grade has no defined assessment here.
Recorded status: established
Recorded scope: every simple 4-regular graph on 1,030,200 vertices, including every eligible Cayley graph in the problem
Complete recorded scope and conditions
{
"kind": "bounded",
"statement": "every simple 4-regular graph on 1,030,200 vertices, including every eligible Cayley graph in the problem",
"bounds": {
"vertices": {
"min": 1030200,
"max": 1030200
},
"degree": {
"min": 4,
"max": 4
}
},
"exhaustive": true
}Originating problem: Largest girth from two generators of SL(2,101)
Authored record and scope
- Authored title
- The Moore bound gives a universal ceiling of 24
- Record type
- claim
- Stored status
- established
- Evidence grade
- proved
- Recorded scope data
- { "kind": "bounded", "statement": "every simple 4-regular graph on 1,030,200 vertices, including every eligible Cayley graph in the problem", "bounds": { "vertices": { "min": 1030200, "max": 1030200 }, "degree": { "min": 4, "max": 4 } }, "exhaustive": true }
2Authored explanation
Suppose a 4-regular graph has girth at least 25. The nonbacktracking paths of length at most 12 starting at a fixed vertex have distinct endpoints. Otherwise two such paths would give a cycle of length at most 24. The graph therefore has at least \[ 1+4(1+3+\cdots+3^{11}) =1+2(3^{12}-1) =1{,}062{,}881 \] vertices. The Cayley graphs in this problem have 1,030,200 vertices, so their girth is at most 24.
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3Evidence
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Verification source: arxiv.org ↗, Gamburd, Hoory, Shahshahani, Shalev, and Virag, On the girth of random Cayley graphs, Section 1 discusses the Moore counting bound; the numerical specialization is shown here
4What was measured
5How it connects
Bounds
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Recorded for
- problem
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Machine-readable record
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"title": "The Moore bound gives a universal ceiling of 24",
"summary": "Girth 25 would require 1,062,881 vertices, which is 32,681 too many.",
"relevance": "For Largest girth from two generators of SL(2,101), record mgsl-claim-moore-upper-bound (“The Moore bound gives a universal ceiling of 24”) records a bound, answer, status fact, or structural consequence. The record states: Girth 25 would require 1,062,881 vertices, which is 32,681 too many.",
"relevance_source": "recorded",
"body": "Suppose a 4-regular graph has girth at least 25. The nonbacktracking paths of length at most 12 starting at a fixed vertex have distinct endpoints. Otherwise two such paths would give a cycle of length at most 24. The graph therefore has at least\n\\[\n1+4(1+3+\\cdots+3^{11})\n=1+2(3^{12}-1)\n=1{,}062{,}881\n\\]\nvertices. The Cayley graphs in this problem have 1,030,200 vertices, so their girth is at most 24.",
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{
"slug": "R519",
"title": "The maximum girth is currently certified between 17 and 24",
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{
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}7Provenance
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