TheoremDB
All problems

[#P26] Smooth four-dimensional Poincaré conjecture

Open problem

Research contributions are available. The problem remains open.

View research
Contents

Problem. Every smooth closed four-manifold \(M\) that is homotopy equivalent to \(S^4\) is diffeomorphic to the standard smooth four-sphere \(S^4\).

Agent accessWork in ChatGPT

The agent reads this problem's research brief and asks you before it saves anything to TheoremDB.

Definitions and notation

1Context

Dimension four is the remaining exceptional dimension for the smooth generalized Poincaré question.

2Definitions

Definition 1 (A homotopy four-sphere). A homotopy four-sphere is a smooth closed four-manifold with the homotopy type of S^4.

Definition 2 (Diffeomorphic). Diffeomorphic means equivalent by a smooth bijection with a smooth inverse.

3What counts as a solution

  • Prove that every smooth homotopy four-sphere is diffeomorphic to S^4, or construct a smooth homotopy four-sphere and prove that it is not diffeomorphic to S^4.

1Status

Saved packet · July 31, 2026

What counts as a solution

Saved packet status (Dated status and exact unresolved remainder). Unresolved in this packet after the dated source check. Strongest checked result: Freedman's theorem gives homeomorphism to S^4. The linked census reduces its six-pentachoron S^4 cases to at most four possible PL classes and conjectures them standard. Exact unresolved remainder: Prove every smooth homotopy 4-sphere is diffeomorphic to S^4, or construct and certify an exotic one.[1]

1Packet records

2 records

Notes and companion material

Original intake status. The cited 2026 article presents the nonexistence of exotic four-spheres as the smooth four-dimensional Poincaré conjecture. The source and public status were checked on 2026-07-31. This is an admin-curated seed record, not an independent exhaustive literature review.

  • The topological four-dimensional Poincaré theorem is known. This record concerns smooth structures and recurring claimed proofs require specialist review.

Computational notes

  • Triangulation censuses can eliminate small combinatorial candidates without classifying all smooth homotopy four-spheres.

2See also

Contribute to this problem
Cite this problem statement

Cite the original sources separately.

Plain text
“Smooth four-dimensional Poincaré conjecture.” TheoremDB. P26. Problem statement; statement text SHA-256 c4cd737641073e267a3c5af1d489119d9a43d7cf12a1230c6312866e99d829f3. https://theoremdb.org/statement/?ref=P26
BibTeX
@misc{theoremdb-problem-c4cd737641073e267a3c5af1d489119d9a43d7cf12a1230c6312866e99d829f3,
  title = {{Smooth four-dimensional Poincaré conjecture}},
  howpublished = {TheoremDB},
  note = {Problem statement; statement text SHA-256 c4cd737641073e267a3c5af1d489119d9a43d7cf12a1230c6312866e99d829f3},
  url = {https://theoremdb.org/statement/?ref=P26}
}

This problem includes 2 records joined by 2 typed links, sourced from link.springer.com[1], current as of July 31, 2026.

1References

  1. Packet source. Small Triangulations of 4-Manifolds and the 4-Manifold Census, Discrete & Computational Geometry (2026). DOI 10.1007/s00454-026-00818-w. Discrete & Computational Geometry, 2026, Conjecture 1 and introduction. ↗website · primary source · checked 2026-07-31Source use: original summary.The cited 2026 article presents the nonexistence of exotic four-spheres as the smooth four-dimensional Poincaré conjecture. The source and public status were checked on 2026-07-22. This is an admin-curated seed record, not an independent exhaustive literature review.Also cited at Abstract, Conjecture 1, and census results.Also cited at Editorial research route recorded 2026-07-31.Source used to formulate or check the problem record.Source used to assess the problem's recorded status.States the smooth four-dimensional Poincaré conjecture and supplies the finite census result without resolving it.Source named by the research packet.

An original CC0 restatement prepared by TheoremDB maintainers.

Discussion

Loading discussion.

Add a comment

Report comment

Flag this problem

Sign in to follow

Sign in in another tab, then return here.

Open sign-in in another tab

Report a problem

Report location:

Your ChatGPT account

Opening ChatGPT

ChatGPT is opening in a new tab.